CameraIcon

SearchIcon

MyQuestionIcon

Trigonometric Ratios

Sec8A-1/sec4A...

Question

Sec8A-1/sec4A-1=tan8A/tan2A

Open in App

Solution

Suggest Corrections

thumbs-up

2

mid-banner-image

mid-banner-image

Similar questions

Evaluate: $\frac{sec 8 A - 1}{sec 4 A - 1} =$

s e c^{4} A - s e c^{2} A = t a n^{4} A + t a n^{2} A

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - {tan}^{2} A}{1 - {cot}^{2} A})}^{2} = {tan}^{2} A

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - {tan}^{2} A}{1 - {cot}^{2} A})}^{2} = {tan}^{2} A

(t a n^{2} A s e c^{2} B - s e c^{2} A t a n^{2} B) =

View More

Join BYJU'S Learning Program

Select...

similar_icon

Related Videos

lock

Trigonometric Ratios

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Trigonometric Ratios

Standard X Mathematics

Join BYJU'S Learning Program

Select...