Question

Seeta Devi has Rs 9 in fifty - paise and twenty five paise coins. She has twice as many twenty-five paise coins as she has fifty-paise coins. How many coins of each kind does she have ?

Answer 1

Total amount = Rs .9

Let fifty paise coins = x

Then twenty-five paise coins = 2x

According to the condition :

$x\times \frac{50}{100}+2x\times \frac{25}{100}=9$

$\frac{x}{2}+\frac{x}{2}=9\Rightarrow x=9$

$\therefore$ Number of fifty - paise coins = 9 and number of twenty five paise coins

$=2x=2\times 9=18$

Check : Amount $=\frac{9\times 50}{100}+\frac{18\times 25}{100}$

$=\frac{9}{2}+\frac{9}{2}=\frac{18}{2}=9$ rupees

Which is given.

Hence our answer is correct.