Select the correct order of basic nature :

{C H}_{3} C H_{2}^{-} > {C H}_{2} = C H^{-} > C H \equiv C^{-} > O H^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{C H}_{3} C H_{2}^{-} > C H \equiv C^{-} > C H_{2} = {C H}^{-} > O H^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{3} C H_{2}^{-} > O H^{-} > C H \equiv C^{-} > {C H}_{2} = C H^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O H^{-} > C H \equiv C^{-} > C H_{2} = C H^{-} > {C H}_{3} {C H}_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ${C H}_{3} C H_{2}^{-} > {C H}_{2} = C H^{-} > C H \equiv C^{-} > O H^{-}$
order of acidic strength is
$H_{2} O > C H \equiv C H > C H_{2} = C H_{2} > C H_{3} C H_{3}$
We know that a stronger acid has weak conjugate base and vice versa, thus the order of basic nature is given compound is
$C H_{3} - {C H}_{2}^{-} > {C H}_{2} = {C H}^{-} > C H \equiv C^{-} > {O H}^{-}$

Suggest Corrections

Similar questions

C H_{3} C H_{2} - C H_{2} - O H

C H_{3} - C H_{2} - C | C H_{3} H - O H

C H_{3} - C H_{2} - C H_{3} | C | C H_{3} - O H

C H_{3} - C H_{2} - C H_{2} - O H

C H_{3} - C H = C H - O H

C H_{3} - C H = C H - C H_{2} - O H

C H_{3} - C H = C H - O H

(a) C H_{2} = C H - O H | C H - C H_{3} [X] - - \to C H_{2} = C H - O | | C - C H_{3}

(a) C l_{2} / N a O H (b) F e n t o n r e a g e n t

(b) K_{2} C r_{2} O_{7} / H^{@} / △

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

Join BYJU'S Learning Program