Question

# Select the correct order of basicity.

A
CH3CH2>CH2=CH>HCC>OH
B
CH3CH2>HCC>CH2=CH>OH
C
CH3CH2>OH>HCC>CH2=CH
D
OH>HCC>CH2=CH>CH3CH2

Solution

## The correct option is A $$\displaystyle CH_{3}CH_{2}^{-}> CH_{2}= CH^{-}> HC\equiv C^{-}> OH^{-}$$A carbanion is the conjugate base of a carbon acid. $$Basic \ strength \ of \ conjugate \ base \displaystyle \propto$$ $$\displaystyle \frac{1}{acidic\: \: strength\: \: of\: \: conjugate\: \: acid}$$ A hydrogen tends to be more acidic when attached to a more electronegative atom. Alkynes are more acidic than alkenes, which are in turn more acidic than alkanes, is that $$sp$$ carbon atoms are more electronegative than $$sp^2$$ carbon atoms, which are in turn more electronegative than $$sp^3$$ carbon atoms.Acidic strength of conjugate acids $$\displaystyle CH_{3}CH_{3}< CH_{2}= CH_2< HC\equiv CH < HOH$$The base strength would be:$$\displaystyle CH_{3}CH_{2}^{-}> CH_{2}= CH^{-}> HC\equiv C^{-}> OH^{-}$$Chemistry

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