CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Seven years ago Varun's age was five times the square of Swati's age. Three years hence Swati's age will be two fifth of Varun's age. Find their present ages.
[4 MARKS]


Solution

Framing of equation: 2 Marks
Calculations: 1 Mark
Answer: 1 Mark

Seven years ago, let Swati's age be x years, Varun's present age =(5x2+7) years

Three years hence, we have

Swati's age =(x+7+3) years=(x+10) years

Varun's age =(5x2+7+3) years=(5x2+10) years

It is given that three years hence Swati's age will be 25 of Varun's age.

x+10=25(5x2+10)

x+10=2x2+4

2x2x6=0

2x24x+3x6=0

2x(x2)+3(x2)=0

(2x+3)(x2)=0

x2=0         [2x+30 as x>0]

x=2

Hence, Swati's pressent age = (2+7) years = 9 years

Varun's present age =(5×22+7) years = 27 years.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...



footer-image