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Hydrogenation of Alkynes

Show by means...

Question

Show by means of reactions, how you will inter-convert cis-trans isomers of hex-3-ene?

B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for cis;

L i, N H_{3}

for trans

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B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for trans;

L i, N H_{3}

for cis

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B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for trans;

N a, N H_{3}

for cis

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B r_{2} / C C l_{4}

;

2. N a N H_{2} / N H_{3}

L i n d l a r P d / C H_{2}

for cis;

N a, N H_{3}

for trans

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

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Solution

The correct options are
A 1. $B r_{2} / C C l_{4}$ ; $2. N a N H_{2} / N H_{3}$ 3. $L i n d l a r P d / C H_{2}$ for cis; $L i, N H_{3}$ for trans
D 1. $B r_{2} / C C l_{4}$ ; $2. N a N H_{2} / N H_{3}$ 3. $L i n d l a r P d / C H_{2}$ for cis; $N a, N H_{3}$ for trans
Start with any isomer and bromine addition across the double bond of hex-3-ene gives 3,4-dibromohexane.

From the above compound, get to hex-3-yne by dehydrohalogenation:

Getting to hex-3-yne is the key. From there it is easy!

Suggest Corrections

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