Question

# Show that the expansion of ${\left({x}^{2}+\frac{1}{x}\right)}^{12}$ does not contain any term involving x−1.

Solution

## Suppose x−1 occurs at the (r + 1)th term in the given expression. Then, Hence, the expansion of ${\left({x}^{2}+\frac{1}{x}\right)}^{12}$ does not contain any term involving x−1.MathematicsRD Sharma XI (2015)Standard XI

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