Question

Show that the number of shot in a square pile is one-fourth the number of shot in a triangular pile of double the number of courses.

Answer 1

No. of shots in a square pile

$=\frac{n(n+1)(2n+1)}{6}$

No. oof shots in a triangular pile

$=\frac{2n(2n+1)(2n+2)}{6}$

$=4\frac{n(n+1)(2n+1)}{6}$

$=4\times$No. of shots in square pile