Show that the progression 3, 9, 15, 21,... is an AP. Write down its first term and the common difference.
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Solution
The given progression is 3, 9, 15, 21,...
Clearly, (9 - 3) = (15 - 9) = (21 - 15) = 6 (Constant)
Thus, each term differs from its preceding term by 6.
So, the given progression is an AP.
Its first term is 3 and the common difference is 6.
Thus, a = 3, and d = 6