Show that $x = 2, y = 1$ is a solution of the system of simultaneous linear equations.
$3 x - 2 y = 4$
$2 x + y = 5$ .

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Solution

The given system of equations is
$3 x - 2 y = 4$ .(i)
$2 x + y = 5$ ..(ii)

Putting $x = 2$ and $y = 1$ in equation (i), we have
LHS $= 3 \times 2 - 2 \times 1 = 4 =$ RHS

Putting $x = 2$ and $y = 1$ in equation (ii), we have
LHS $= 2 \times 2 + 1 \times 1 = 5 =$ RHS

Thus, $x = 2$ and $y = 1$ satisfy both the equations of the given system.

Hence, $x = 2$ , $y = 1$ is a solution of the given system.

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