SI unit of coefficient of viscosity is:

P a / s

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P a . s

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N / (m^{2}

/ u n i t v e l o c i t y

)

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N / (m

/ u n i t v e l o c i t y g r a d i e n t

)

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Solution

The correct option is B $P a . s$
Coefficient of viscosity $= \frac{F r}{A v} = \frac{(M^{1} L^{1} T^{- 2}) (L)}{(L^{2}) (L^{1} T^{- 1})} = M^{1} L^{- 1} T^{- 1}$

$\frac{P a s c a l}{S} = \frac{M^{1} L^{- 1} T^{- 2}}{T^{1}} = M^{1} L^{- 1} T^{- 3}$

$P a s c a l - s = M^{1} L^{- 1} T^{- 2} \times T^{1} = M^{1} L^{- 1} T^{- 1}$

$N / m^{2} /$ unit velocity $= \frac{M^{1} L^{1} T^{- 2}}{L^{2} L T^{- 1}} = M^{1} L^{- 2} T^{- 1}$

$N / m /$ unit velocity grad $= \frac{M^{1} L^{1} T^{- 2}}{L (\frac{L T^{- 1}}{L})} = M^{1} L^{0} T^{- 1}$

Hence, option B is correct.

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Similar questions

What is SI unit of viscosity coefficient $(η)$ ?

(a) Pascal (b) $N s m^{- 2}$ (c) $k m^{- 2} s$ (d) $N m^{- 2}$

S I

η

7 c m

0.8 P a . s

20 c m . s^{- 1}

N .

(η)

2.76 \times 10

^{- 4}

- 40

^{o}

5984

^{- 1}

η

- 50^{o}

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