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Question

Sides AB and AC of a ABC are equal. BC is produced through C upto point D such that AC = CD.

D and A are joined and produced (through vertex A) upto point E.

If BAE = 1080; find ADB.

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Solution

In Δ ABD,


BAE=3+ADB

108= 3+ADB

But AB = AC

3= angle2

108= 2+ADB……(i)

Now,

In Δ ACD,

2=1+ADB

But AC = CD

1=ADB

2=ADB+ADB

2=2ADB

Putting this value in (i)

108 = 2ADB+ADB

3ADB=1080

ADB=360


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