Question

# Silver $$(atomic mass \, = \, 108 g \, mol^{-1})$$ has density of $$10.5 g/cm^3$$. The number of silver atoms on a surface area of $$10^{-12}m^2$$ can be expressed in scientific notations as $$Y \, \times \, 10^X$$. The value of X is :

Solution

## Density of silver $$= 10.5 g /cm^{3}$$surface area $$=10^{-12}m^{2}$$Number of mole $$=\dfrac{10.5\times 10^{6}\times 10^{-12}}{108}mol/m$$                            $$=10^{-7} mol/m$$Number of atom $$=6.022 \times 10^{23}\times 10^{-1}mol/m$$                             $$=6.022\times 10^{16} mol/m$$                        $$X=16$$Chemistry

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