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Stoichiometry

Silver atom...

Question

Silver $(a t o m i c m a s s = 108 g m o l^{- 1})$ has density of $10.5 g / c m^{3}$ . The number of silver atoms on a surface area of $10^{- 12} m^{2}$ can be expressed in scientific notations as $Y \times 10^{X}$ . The value of X is :

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Solution

Density of silver $= 10.5 g / c m^{3}$
surface area $= 10^{- 12} m^{2}$
Number of mole $= \frac{10.5 \times 10^{6} \times 10^{- 12}}{108} m o l / m$
$= 10^{- 7} m o l / m$
Number of atom $= 6.022 \times 10^{23} \times 10^{- 1} m o l / m$
$= 6.022 \times 10^{16} m o l / m$
$X = 16$

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