- p - q is equal toA - - p - qB- P - qC- p - qD - - p - q

The correct option is B p ∧ q(∼ (∼ p))∧ q=p ∧ q ...

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Negation

∼∼ p ∧ q is e...

Question

$\sim (\sim p)) \land q$ is equal to

\sim p \land q

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p \land q

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p \land \sim q

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\sim p \land \sim q

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Solution

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Similar questions

\sim ((\sim p) \land q)

\sim (\sim p)) \land q

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$\sim (\sim p \land q)$ is logically equivalent to

(p \land \sim q) \lor q \lor (\sim p \land q)

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