Now, (1 i)(1+1i) =(1 i)(1 i) [ Since 1i= i as i^2= 1 ] =1^2+i^2+2i = 2i = 2i . ...

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Simplify: 1-...

Question

Simplify:
$(1 - i) (1 + \frac{1}{i})$ .

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Solution

Now,
$(1 - i) (1 + \frac{1}{i})$
$= (1 - i) (1 - i)$ [ Since $\frac{1}{i} = - i$ as $i^{2} = - 1$ ]
$= 1^{2} + i^{2} + 2 i$
$= - 2 i$
$= - 2 i$ .

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