Byju's Answer
Standard XII
Mathematics
Special Integrals - 1
Simplify : ...
Question
Simplify :
2
4
√
81
−
8
3
√
216
+
15
5
√
32
+
√
225
−
4
√
16
A
0
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B
1
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C
−
1
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D
2
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Solution
The correct option is
B
1
2
4
√
81
−
8
3
√
216
+
15
5
√
32
+
√
225
−
4
√
16
2
(
3
4
)
1
4
−
8
(
6
3
)
1
3
+
15
(
2
5
)
1
5
+
(
15
2
)
1
2
−
(
2
4
)
1
4
2
×
(
3
)
−
8
(
6
)
+
15
(
2
)
+
15
−
2
6
−
48
+
30
+
15
−
2
=
1
Suggest Corrections
0
Similar questions
Q.
Simplify :
4
√
81
−
8
3
√
216
+
15
5
√
32
+
√
225
Q.
Simplify:
4
√
81
−
8
3
√
216
+
15
5
√
32
+
√
225
Q.
Simplify:
4
√
81
+
2
5
√
32
−
8
√
225
+
3
√
216
Q.
Simplify :
4
√
81
−
8
3
√
216
+
15
3
√
32
+
√
225
.
Q.
Simplify:
(
81
)
3
4
−
(
1
32
)
−
2
5
+
8
1
3
(
1
2
)
−
1
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