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B
b(6a2+b2)
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C
2b(12a3+b3)
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D
b2(6a+b)
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Solution
The correct option is A2b(12a2+b2) (2a+b)3−(2a−b)3 =[(2a)3+3(2a)2(b)+3(2a)(b)2+(b)3]−[(2a)3−3(2a)2(b)+3(2a)(b)2−(b)3] =12a2b+b3+12a2b+b3 =24a2b+2b3 =2b(12a2+b2).