Simplify: $(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)$

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$- 4 y^{2} + 6 x y$

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$2 y (- 2 y + 3 x)$

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B o t h b a n d c

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Solution

The correct option is D $B o t h b a n d c$
$(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)$

Using identity $(a + b) (a - b) = a^{2} - b^{2}$ ,
$(3 x + 2 y) (3 x - 2 y) = 9 x^{2} - 4 y^{2}$

So, $(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)$
= $(9 x^{2} + 6 x y - 8 y^{2}) - [9 x^{2} - 4 y^{2}]$
= $- 4 y^{2} + 6 x y$

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Similar questions

Simplify: (3x-2y)(3x+4y)-(3x+2y)(3x-2y)

\frac{(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)}{(- 4 y^{2} + 6 x y)}

(3 x - \frac{1}{2 y}) (3 x + \frac{1}{2 y})

9 x^{2} - 4 y^{2}

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