Simplify:
$(a + b + c)^{2} - 4 (a + b + c) - 21$

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Solution

Now,
$(a + b + c)^{2} - 4 (a + b + c) - 21$
$= (a + b + c)^{2} - 7 (a + b + c) + 3 (a + b + c) - 21$
$= (a + b + c - 7) (a + b + c + 3)$ .

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