Question

Simplify and express in exponential form :
$\frac{(9^3{)}^2\times 7^4}{3^8\times 21}$

Answer 1

$\frac{(9^3{)}^2\times 7^4}{3^8\times 21}$

$=\frac{(9{)}^{3\times 2}\times 7^4}{3^8\times 7\times 3}$

$=\frac{9^6\times 7^4}{3^9\times 7}$

$=\frac{9^6\times 7^{4-1}}{3^9}=\frac{9^6\times 7^3}{39}$

$=\frac{(3^2{)}^6\times 7^3}{39}=\frac{3^{12}\times 7^3}{39}$

$=3^{12-9}\times 7^3=3^3\times 7^3$

$(21{)}^3=21\times 21\times 21=9261$