Question

Simplify:
$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}+\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$

• A. $4\sqrt{6}$
• B. $10$
• C. $2$
• D. $\frac{4\sqrt{6}}{5}$

Answer 1

Answer: (B)

$10$

$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}+\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}=\frac{(\sqrt{3}+\sqrt{2}{)}^2+(\sqrt{3}-\sqrt{2}{)}^2}{3-2}=\frac{3+2+3+2}{1}=10$