Simplify: ${2 x}^{2} y - {3 x y}^{2} + {2 x}^{2} y - {4 x}^{2} y + {2 x y}^{2}$

{4 x}^{2} y + {2 x y}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{2 x}^{2} y - 8 x y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- x y^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- x y - 2 x + y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $- x y^{2}$
${2 x}^{2} y - {3 x y}^{2} + {2 x}^{2} y - {4 x}^{2} y + {2 x y}^{2}$
$= ({2 x}^{2} y + {2 x}^{2} y - {4 x}^{2} y) + (- {3 x y}^{2} + {2 x y}^{2}),$ (Arranging like terms together)
$= 0 - {x y}^{2} = - {x y}^{2}$
Hence simplified form of the given expression is $- x y^{2}$

Suggest Corrections

Similar questions

x^{2} y^{2} - 2 x y^{2} - 3 y^{2} - 4 x^{2} y + 8 x y + 12 y = 0

If we subtract $- 4 x^{2} y$ from $2 x^{2} y$ we get:

Question 60 (a)

What should be subtracted from $2 x^{3} - 3 x^{2} y + 2 x y^{2} + 3 y^{3}$ to get $x^{3} - 2 x^{2} y + 3 x y^{2} + 4 y^{3} ?$

x^{2} y^{2} - 2 x y^{2} - 3 y^{2} - 4 x^{2} y + 8 x y + 12 y = 0

Join BYJU'S Learning Program