Question

Simplify the expression:
$\frac{9}{14a^3}$ ÷ $\frac{12}{21a^3}$ =

• A. 3/4
• B. 9/8
• C. 7/9
• D. 3/7

Answer 1

The correct option is B 9/8

Given:
$\frac{9}{14a^3}$ ÷ $\frac{12}{21a^3}$

Using the division rule and flipping the second fraction, we have,
$\frac{9}{14a^3}$ × $\frac{21a^3}{12}$

= $\frac{3}{2a^3}$ × $\frac{3a^3}{4}$

Using the property $x^m÷x^n=x^{m-n}$, we get,

$\frac{3}{2}$ × $\frac{3a^{3-3}}{4}$

= $\frac{9}{8}$ [∵ $a^{3-3}$ = 1]

Therefore,
$\frac{9}{14a^3}$ ÷ $\frac{12}{21a^3}$ = $\frac{9}{8}$