Simplify $(x + 3) (x + 5)$ .

$x^{2} + 6 x + 9$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x^{2} + 8 x + 15$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$x^{2} + 9 x + 6$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$9 x^{2} + 6 x + 9$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$x^{2} + 8 x + 15$

To simplify: $(x + 3) (x + 5)$

Using the identity $[(x + a) (x + b)^{2} = x^{2} + (a + b) x + a b]$
we get,

$(x + 3) (x + 5) = x^{2} + (3 + 5) x + 3 \times 5 = x^{2} + 8 x + 15$

Suggest Corrections

Similar questions

9 x^{2} + 6 x y z + 3 x - 24 x^{2} + 6 x

∣ ∣ ∣ ∣ \begin{matrix} x + 2 & x + 3 & x + 5 x + 4 & x + 6 & x + 9 x + 8 & x + 11 & x + 15 \end{matrix} ∣ ∣ ∣ ∣

Factorise: 9 x^{2} - 24 x + 16

\frac{6 x^{2} + 13 x - 5}{9 x^{2} + 3 x - 2} \times \frac{3 x^{2} - 10 x - 8}{16 x^{2} - 1} .

What remains when $6 x - 2 x^{2}$ is taken away from $3 x + 7 x^{2}$ ?

Join BYJU'S Learning Program