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Question

Simplify:
$$(y^3-5y^2)\div y\times (y-1)$$, then the answer is $$y^3-6y^2+5y$$
 If true then enter $$1$$ and if false then enter $$0$$


Solution

using BODMAS
$$\cfrac { (y^{ 3 }-5y^{ 2 }) }{ y } *(y-1)\\ =\quad (y^{ 2 }-5y)*(y-1)\quad \\ =\quad y^{ 3 }-5y^{ 2 }-y^{ 2 }+5y\\ =\quad y^{ 3 }-6y^{ 2 }+5y$$

Mathematics

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