Simpllify $: 2 x^{2} + 5 x - 1 + 8 x + x^{2} + 7 - 6 x + 3 - 3 x^{2}$

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Solution

$2 x^{2} + 5 x - 1 + 8 x + x^{2} + 7 - 6 x + 3 - 3 x^{2}$
$= 3 x^{2} - 3 x^{2} + 13 x - 6 x + 10 - 1$
$= 7 x + 9$ Ans.

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Similar questions

2 x^{2} + 5 x - 1 + 8 x + x^{2} + 7 - 6 x + 3 - 3 x^{2}

2 x^{2} + 5 x - 1 + 8 x + x^{2} + 7 - 6 x + 3 - 3 x^{2}

Subtract: 2 x^{2} + 6 - 4 x from 3 x^{2} - 6 x + 8.

2 x^{2} + 6 - 4 x

3 x^{2} - 6 x + 8

\sqrt{2 x^{2} + 5 x - 7} + \sqrt{3 (x^{2} - 7 x + 6)} - \sqrt{7 x^{2} - 6 x - 1} = 0