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Question

$$\sin { { 24 }^{ 0 } } +\sin { { 32 }^{ 0 } } +\sin { { 204 }^{ 0 } } +\sin { { 212 }^{ 0 } } =$$


A
1
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B
1
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C
0
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D
2
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Solution

The correct option is C $$0$$
Given,

$$\sin 24 + \sin 32 + \sin 204 + \sin 212 $$

$$= \sin 24 + \sin 32 + \sin (180+24) + \sin (180 +32) $$

$$= \sin 24 + \sin 32 - \sin 24 - \sin 32 $$

$$=0$$

Maths

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