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Question

sin6A+cos6A+3sin2Acos2A=


A

0

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B

1

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C

2

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D

3

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Solution

The correct option is B

1


1

We have:

sin6A+cos6A+3(sin2A)(cos2A)

=(sin6A)3+(cos2A)3+3(sin2A)(cos2A)×1

=(sin2A)3+(cos2A)3+3(sin2A)(cos2A)(sin2A+cos2A)

=(sin2A+cos2A)

=13=1


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