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Question

$$\sin \theta \cos (90 - \theta) + \cos \theta \sin (90 - \theta) = $$


A
0
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B
1
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C
2
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D
32
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Solution

The correct option is A $$1$$
Given,
$$\sin { \theta  } \cos { \left( { 90^o-\theta  }  \right) +\cos { \theta  } \sin { \left( { 90^o-\theta  }  \right)  }  } $$
 $$=\sin { \theta  } \sin { \theta  } +\cos { \theta  } \cos { \theta  } $$
$$=\sin ^{ 2 }{ \theta +\cos ^{ 2 }{ \theta  }  } $$
 $$=1$$
1 is the answer

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