CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Sinusoidal waves 5.00 cm in amplitude are to be transmitted along a string having a linear mass density equal to 4.00×102kg/m. If the source can deliver an average power of 90W and the string is under a tension of 100 N, then the frequency at which the source can operate is (take π2=10).

A
45 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
50 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
30 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
62 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 30 Hz
Given,
A=5cm=0.05m
μ=4×102kgm
Pavg=90w
T=100N
π210
To find, f=?
Power transmitted by string wave =12μω2A2v
Here, v=Tμ=1004×102
v=12×102=0.5×102ms
P=12μω2A2v
2PμA2v=ω2
ω2=2×904×102×(0.05)2×0.5×102=1804×0.5×(0.05)2=3.6×104
ω2=(2πf)2
4π2f2=3.6×104
f2=900
f=30Hz
The frequency at which the source can operate is 30Hz
Hence, option C is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Wave Reflection and Transmission
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon