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Question

Six boys and girls sit in a row randomly. Find the probability that the boys and girls sit alternately.

A
p=1311040
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B
p=1924
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C
p=1462
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D
p=1231
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Solution

The correct option is B p=1462
Total number of boys and girls =6+6=12
Total cases n=12!
Since the boys and girls can sit alternately in 6! 6! ways if we begin with a boy and similarly they can sit alternately in 6! 6! ways if we begin with a girl.
m=2×6!6!
Hence p=mn=2×6!6!12!
p=1462

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