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Question

Six lead-acid type of secondary cells each of emf 2.0 V and internal resistance of 0.015  are joined in series to provide a supply to a resistance of 8.5 . What are the current drawn from the supply and it's terminal voltage?


A
11.8749
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B
12.8749
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C
13.1749
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D
10.5749
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Solution

The correct option is A $$11.8749 $$
$$ VT= V - i r\\ VT = 12 - 1.39 \times 0.09\\ VT =11.8749 $$

Physics

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