Question

Six men can do a certain piece of work in (5𝑥 + 6) days and 11 men can do the same
work in 3𝑥 days. Find the value of 𝑥.

Answer 1

Case 1
No. of men at First=6
No. of days = (5𝑥 + 6)
Work=6*(5x+6)
Case 2
No.of men at second=11
No.of days = 3x
Work = 11*3x

Given Work completed at same time
So Case1=Case2
6*(5𝑥 + 6) = 11*3x
6*5x+6*6=33x
30x+36=33x
->36=33x-30x
->36=3x
->36/3=x
->x=12