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Question

Six taps can fill an empty cistern in $$8$$ hours. How much more time will be taken, if two taps go out of order? Assume all the taps supply water at the same rate.


A
1 hour
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B
2 hours
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C
3 hours
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D
4 hours
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Solution

The correct option is B $$4$$ hours
Given six taps fill an empty cistern in $$8$$ hours
If two taps go out of order then no. of taps $$= 6-2 = 4$$
Then $$\dfrac{6}{4}=\dfrac{x}{8}$$
$$\Longrightarrow 4x=6\times 8$$
$$\Longrightarrow x=\dfrac{48}{4}=12$$ hours
Then, more time $$= 12-8=4$$ hours.

Mathematics

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