Question

# Six taps can fill an empty cistern in $$8$$ hours. How much more time will be taken, if two taps go out of order? Assume all the taps supply water at the same rate.

A
1 hour
B
2 hours
C
3 hours
D
4 hours

Solution

## The correct option is B $$4$$ hoursGiven six taps fill an empty cistern in $$8$$ hoursIf two taps go out of order then no. of taps $$= 6-2 = 4$$Then $$\dfrac{6}{4}=\dfrac{x}{8}$$$$\Longrightarrow 4x=6\times 8$$$$\Longrightarrow x=\dfrac{48}{4}=12$$ hoursThen, more time $$= 12-8=4$$ hours.Mathematics

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