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Question

Six years ago a man was three times as old as his son. In 6 years time, he will be twice as old as his son. Find their present ages

A
30,15
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B
40,20
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C
42,18
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D
41,19
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Solution

The correct option is C 42,18
Let the present ages of father and son be x and y, respectively.
As per the problem, six years ago,
(x6)=3(y6)
Six years later, (x+6)=2(y+6)
Solving these two equations, we get father's age is 42 years, and son's age is 18 years.

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