Question

# Sixty percent of given sample of oxygen gas when raised to a high temperature dissociates into atoms. Ratio of its initial heat capacity (at constant volume) to the final heat capacity (at constant volume) will be242825261072527

Solution

## The correct option is C 107Let, initially no2 has 1 mole 0.6n of O2 dissociates to 1.2n of O  So, mixture consists of 0.4n of O2 and 1.2n of O.  CV=fR2 (CV)mix=1.2n×CV1+(0.4n)CV2((1.2+0.4) (CV)mix=1.2×32×R+0.4×52×R1.6 Final heat capacity =(1.8+1)R1.6=74R Initial heat capacity =52R (CV)i(CV)f=5274=107

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