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Standard XII

Physics

Phase Difference

Small amplitu...

Question

Small amplitude progressive wave in a stretched string has a speed of 100 cm/s, and frequency 100 Hz. The phase difference between two points 2.75 cm apart on the string in radians, is

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Solution

The correct option is B

$v = 1 m / s, f = 100 H z λ = \frac{v}{f} = \frac{1}{100} m = 1 c m Δ ϕ = \frac{2 π}{λ} \times 2.75 r a d = 5.5 π r a d = \frac{11 π}{2} r a d$

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Small amplitude progressive wave in a stretched string has a speed of 100 cm/s, and frequency 100 Hz. The phase difference between two points 2.75 cm apart on the string in radians, is

The correct option is B v=1m/s,f=100 Hzλ=vf=1100m=1cmΔϕ=2πλ×2.75 rad=5.5π rad=11π2rad

The correct option is B

$v = 1 m / s, f = 100 H z λ = \frac{v}{f} = \frac{1}{100} m = 1 c m Δ ϕ = \frac{2 π}{λ} \times 2.75 r a d = 5.5 π r a d = \frac{11 π}{2} r a d$