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Byju's Answer
Standard VII
Mathematics
Simple Interest
Smith investe...
Question
Smith invested
5000
f
o
r
t
w
o
y
e
a
r
s
.
F
o
r
t
h
e
f
i
r
s
t
y
e
a
r
,
t
h
e
r
a
t
e
o
f
i
n
t
e
r
e
s
t
w
a
s
7
8.5
)
Open in App
Solution
⇒
Smith invested
$
5000
for two years.
For first year rate of interest is
7
%
and for second year is
8.5
%
.
⇒
Interest at the end of the first year
⇒
I
=
7
%
×
5000
=
7
100
×
5000
=
$
350
⇒
Interest at the end of the second year
⇒
I
=
8.5
%
×
(
5000
+
350
)
=
8.5
100
×
5350
=
$
454.75
⇒
Total Interest at the end of the two year period is
⇒
$
350
+
$
454.75
=
$
804.75
≈
$
805
Suggest Corrections
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5$ year period?
Q.
A certain investment earned a fixed rate of 4 percent interest per year, compounded annually, for five years. The interest earned for the third year of the investment was how many dollars greater than that for the first year?
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Q.
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