Question

Sodium metal crystallize as a body centred cubic lattice with the cell edge $4.29\mathring{A}$ .What is the radius of sodium atom.

• A. $1.857\times {10}^{-8}cm$
• B. $2.371\times {10}^{-7}cm$
• C. $3.817\times {10}^{-8}cm$
• D. $9.312\times {10}^{-7}cm$

Answer 1

Answer: (A)

$1.857\times {10}^{-8}cm$

Radius of Na atom in a body centered cubic lattice = $\frac{\sqrt{3}\times a}{4}$

$Given:a=4.29A^o$

= $\frac{\sqrt{3}\times 4.29}{4}$

= $1.857A^o$ = $1.857\times {10}^{-8}cm$

Hence,option A is correct.