Question

Sodium metal crystallizes in B.C.C lattice with edge length of $4.29\dot{A}$. The radius of sodium atom is

• A. $2.857\dot{A}$
• B. $1.601\dot{A}$
• C. $2.145\dot{A}$
• D. $1.857\dot{A}$

Answer 1

The correct option is D

$1.857\dot{A}$

In B.C.C., $r=\frac{\sqrt{3}}{4}a$
$r=\frac{\sqrt{3}}{4}\times 4.29=1.857\ddot{A}$