CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Solution A,B and C of the same strong electrolyte offered resistances of $$50\ \Omega,\  100\ \Omega,\  and\ 150\ \Omega$$ in a given conductivity cell. The resistance observed if they are mixed in a volume proportion which is reciprocal of their resistances and tested in the same conductivity cell would be:


A
67.3 Ω
loader
B
81.8 Ω
loader
C
100 Ω
loader
D
300 Ω
loader

Solution

The correct option is A $$67.3\ \Omega$$
Let value be $$v_1,\ v_2$$ and $$v_3$$
$$\dfrac {v_1}{R_1}+\dfrac {v_2}{R_2}+\dfrac {v_3}{R_3}=\dfrac {v_1 +v_2 +v_3}{Req}$$
$$R_1=52\ \Omega\ R_2=100\ \Omega \ R_3=150\ \Omega$$
$$v_1=\dfrac {1}{50}\ v_2=\dfrac {1}{100}\ v_3=\dfrac {1}{150}$$
$$\dfrac {v_1}{R_1}+\dfrac {v_2}{R_2}+\dfrac {v_3}{R_3}=\dfrac {v_1 +v_2 +v_3}{Req}$$
$$\dfrac {1}{50\times 50}+\dfrac {1}{100\times 100}+\dfrac {1}{150\times 150}=\dfrac {\dfrac {1}{50}+\dfrac {1}{100}+\dfrac {1}{150}}{Req}$$
$$\dfrac {36+9+4}{150\times 50\times 4}=\dfrac {\dfrac {6+3+2}{900}}{Req}$$
$$Req\ \dfrac {49}{150\times 150\times 4}=\dfrac {11}{300}$$
$$Req\ =\dfrac {3300}{49}=67.3\ \Omega$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image