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Question

Solution for the given system of equation is

x+y82 = x+2y148 = 3x+y1211


A

(1,-1)

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B

(2,6)

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C

(2,2)

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D

(0,1)

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Solution

The correct option is B

(2,6)


x+y82 = x+2y148 8(x + y - 8) = 2(x + 2y - 14) 3x + 2y - 18 = 0 -----------(i)

x+2y148 = 3x+y1211 11(x +2 y - 14) = 8(3x + y - 12) -13x + 14y - 58 = 0 -----------(ii)

Multiply (i) by 7, 21x + 14y - 126 = 0 -----------(iii)

then subtract from (iii) from (ii); we get

34x = 68 x = 2

y = 6 [by substituting value of x=2 in (i)]


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