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Question

Solution of $$100ml$$ water contains $$0.73g$$ of $$Mg(HCO_3)_2$$ and $$0.81g$$ of $$Ca(HCO_3)_2$$. Calculate the hardness in terms of ppm of $$CaCO_3$$.


A
102ppm
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B
104ppm
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C
5×103ppm
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D
103ppm
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Solution

The correct option is D $$10^4 ppm$$
$$ppm$$ of $$CaCO_3=\dfrac{\left(\dfrac{0.73}{146} + \dfrac{0.81}{162}\right)\times 100}{100} \times 10^6 = 10^4ppm$$

Chemistry

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