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Question

Solution to the differential equation x+x33!+x55!+.....1+x22!+x44!+.....=dxdydx+dy is

A
2ye2x=C.e2x+1
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B
2ye2x=C.e2x1
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C
ye2x=C.e2x+2
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D
2xe2y=C.ex1
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Solution

The correct option is B 2ye2x=C.e2x1

Applying C and D, we get
dydx=exex=e2x2y=e2x+C
or 2ye2x=C.e2x1.

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