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Question

Solve 12sinθ2cosθ+cotθ=0, (0<θ<2π).

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Solution

(cosθ+sinθ)[1sinθ2]=0
sinθ=12,tanθ=1=tan(π4)
θ=π6,ππ6,π+(π4),2π+(π4)
θ=π6,5π6,3π4,7π4 in the given range.

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