Solve (−2−1−1−1)÷(4−1+6−1)
((−12)−1)÷((14)+(16))=((−1−22)÷(3+212))=(−32)÷(512)=(−32)×(125)=(−185)=−3.6
Number of joules in 1 kWh is
1+23.12+2.53.6(12)2.+2.5.83.6.9(12)3 + .... =