Question

Solve :

$4\sqrt{3}{x}^2$ + $5x$ - $2\sqrt{3}$ = 0

Answer 1

given, $4\sqrt{3}{x}^2+5x-2\sqrt{3}=0$

$4\sqrt{3}{x}^2+8x-3x-2\sqrt{3}=0$

$4x(\sqrt{3}x+2)-\sqrt{3}(\sqrt{3}x+2)=0$

$(\sqrt{3}x+2)(4x-\sqrt{3})=0$

$x=\frac{-2}{\sqrt{3}},\frac{\sqrt{3}}{4}$