CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve : 4x=28 by the trial-and-error method.

Open in App
Solution

From above 4x=28

At x=1, LHS=4×1=428

At x=2, LHS=4×2=828

At x=3, LHS=4×3=1228

At x=4, LHS=4×4=1628

At x=5, LHS=4×5=2028

At x=6, LHS=4×6=2428

At x=7, LHS=4×7=28=28

x=7 is the root of the equation

flag
Suggest Corrections
thumbs-up
24
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon