Question

Solve: $5x-2(2x-7)=2(3x-1)+\frac{7}{2}$.

Answer 1

Given, $5x-2(2x-7)=2(3x-1)+\frac{7}{2}$

$⟹$ $5x-4x+14=6x-2+\frac{7}{2}$ ...[By Distribution Law]

$⟹$ $x+14=6x-2+\frac{7}{2}$ ...[On simplifying]

$⟹$ $x-6x=-14-2+\frac{7}{2}$ ...[Transposing $x$ terms to one side]

$⟹$ $-5x=-16+\frac{7}{2}$ ...[On simplifying]

$⟹$ $5x=16-\frac{7}{2}$ ...[Multiplying $-1$ on both sides]

$⟹$ $5x=\frac{32-7}{2}$ …[Cross-multiplying the denominators on the RHS]

$⟹$ $5x=\frac{25}{2}$

$⟹$ $x=\frac{25}{10}=\frac{5}{2}$.