Question

Solve by trial and error method:$z-3=2z-5$

Answer 1

$z-3=2z-5$

At $z=0$, LHS$=0-3=-3$, RHS$=0-5=-5$

$LHS\ne RHS$

At $z=1$, LHS$=1-3=-2$, RHS$=2\left(1\right)-5=-3$

$LHS\ne RHS$

At $z=2$, LHS$=2-3=-1$, RHS$=2\left(2\right)-5=-1$

$LHS=RHS$

$\therefore z=2$ is the root